- Jul 1, 2007I repeat to corredt my previous message

Dear Alexei and Jean-Pierre

another approach that needs an elementary

construction is the following:

but I can not give a synthetic proof.

If X, Y are points on the sides AB, AC

XY is parallel of antiparallel to BC

and the perpendicular bisector of XY meets

the radical axis of the excircles (Ib), (Ic)

or the radical axis of (I), (Ia) at the point Z

then the circumcircle of XYZ is tangent to

(Ib), (Ic) or to (I), (Ia).

Jean-Pierre what is the general statement

of the property of hyperbola you used?

Best regards

Nikos Dergiades

> [Alexei]

___________________________________________________________

> > Let the points X, Y be on the sidelines AC, BC of

> the triangle ABC

> > and XY is parallel to AB. Then there exists a

> circle passing through

> > X, Y and touching two excircles of the triangle.

>

>[JPE] More precisely :

> - there exists a circle through X, Y touching the

> A-excircle and the B-

> excircle

> - there exists a circle through X, Y touching the

> incircle and the C-

> excircle

> We have the same result if XY is antiparallel to AB

>

> Here are some remarks (I've changed the notations

> and I didn't find a

> synthetic proof)

> Let I,Ia,Ib,Ic be the incenter and excenters; U,U'

> the feet on BC of

> the internal and external A-bisectors

> Then there exists

> - an hyperbola h with center U going through the 4

> projections of I and

> Ia upon AB and AC (the asymptots are BC and the

> other common tangent

> through U to the incircle and the A-excircle)

> - an hyperbola h' with center U' going through the 4

> projections of Ib

> and Ic upon AB and AC (the asymptots are BC and the

> other common

> tangent through U' to the B- and C-excircles)

>

> Consider a point M lying on h; the parallel and

> antiparallel to BC

> through M intersect AB and AC at four points lying

> on a circle, and

> this circle touches the incircle and the A-excircle

> (and the line

> through the contact points goes through U)

> Consider a point M' lying on h'; the parallel and

> antiparallel to BC

> through M' intersect AB and AC at four points lying

> on a circle, and

> this circle touches the B-excircle and the

> C-excircle (and the line

> through the contact points goes through U')

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