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13488Re: [EMHL] Mittenpunkt And Concurrency Of Three Euler Lines

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  • Quang Tuan Bui
    Jul 1, 2006
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      Dear Antreas and All My Friends,
      Here are some results for the case:
      Q=incenter I and fixed, line is OH, P is any point on the line connected Gergonne point and Mittenpunkt point. The concurrent point of three Euler lines as Pe.
      (These results may be helpful for general case)
      In the triangle PBcCb denote:
      circumcircle as (Oa)
      orthocenter as Ha,
      altitude foot from Bc as B'c
      altitude foot from Cb as C'b.
      Similarly with another triangles:
      PCaAc we have (Ob), Hb, C'a, A'c,
      PAbBa we have (Oc), Hc, A'b, B'a.
      Denote some intersections of lines:
      Ah = AbA'b /\ AcA'c
      Bh = BcB'c /\ BaB'a
      Ch = CaC'a /\ CbC'b
      1. Six points: B'c, C'b, C'a, A'c, A'b, B'a are on one conic (C1)
      2. The circle (Oa) is tangent with line AbAc. Similarly for (Ob), (Oc). Other than P, these three circles cut each other at three point: Ap = (Ob) /\ (Oc), similarly define Bp, Cp. Denote circumcircle of ApBpCp as (Op).
      3. Six points: Ha, Hb, Hc, Ah, Bh, Ch are on one conic (C2).
      4. Pe is one intersection of circle (Op) and conic (C2).
      Some special nice cases:
      - When P is mittenpunkt then conic (C1) is a circle.
      - When P is centroid then conic (C2) is a circle (Op).
      Best regards,
      Bui Quang Tuan

      Quang Tuan Bui <bqtuan1962@...> wrote: Dear Antreas,
      I have got a very nice first result:
      - Q is fixed and is incenter I
      - Line is OH
      The locus (or at least all points on this line) is line connected mittenpunkt and Gergonne point.
      So mittenpunkt is NO VERY SPECIAL CASE.
      Best regards,
      Bui Quang Tuan

      Quang Tuan Bui wrote:
      Dear Antreas,
      Very nice idea! I try only some special case and we should do together to get some general results.
      I am trying with first case: Q is fixed, and line is OH. I see the locus may be nice: one line?
      The mittenpunkt may be is one very special case: Q = incenter I and the locus is only one point: mittenpunkt or some points?
      These conjectures may be the good reasons for our efforts.
      Best regards,
      Bui Quang Tuan
      PS: Please note that these only conjectures. I can confirm only with my first mittenpunkt message.

      Antreas P. Hatzipolakis wrote:
      On 1-07-06, Quang Tuan Bui wrote (partly):

      > Given triangle ABC, mittenpunkt Mp, incenter I. One line passing
      > through Mp perpendicular to IA cuts lines AB, AC at Ab, Ac respectively.
      > Similarly define Bc, Ba, Ca, Cb.
      > 4. The most interesting:
      > Three Euler lines of triangles MpBcCb, MpCaAc, MpAbBa are concurrent
      > at one point P.

      Dear Tuan

      We have here two interesting locus families

      Let ABC be a triangle, and Q,P two points.
      The perpendicular to QA through P intersects AB,AC at Ab,Ac, resp.
      Similarly Bc,Ba, and Ca,Cb.

      Which is the locus 1. of P 2. of Q
      such that the OH lines (Euler Lines) of PBcCb, PCaAc, PAbBa
      are concurrent.

      Case 1 : Q = Fixed Point, P = Variable Point

      Case 2 : Q = Variable Point, P = Fixed Point

      Special Cases : P, or Q = I,O,H,G,K, etc

      And of course we can ask for concurrence of other than OH lines


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