11044Re: [EMHL] Steiner circumconic, X(1962)...
- Feb 1, 2005Dear Paul and Bernard
> > [PY] Given a point P, can you find a point Q so that thecentroids of
> > the cevian triangle of Q is the same as the centroid ofanticevian
> > triangle of P?aP is
> > [BG]: There are at most three such points Q.
> > one of them is aP/G (cevian quotient or Ceva conjugate) where
> > the anticomplement of P.known,
> > *** If there are at most three such points and one of them is
> > it seems that the other two can be described as theintersections of
> > a conic and a line.They are the common points of the circumconic with center P and the
trilinear polar of i.h.i(q) where q = aP/G, i = isotomic
conjugation, h = homothecy (G,1/4).
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