10974Re: [EMHL] circumcevian reflections
- Jan 5, 2005Dear Floor and friends,
may I wish all the best to all of you for this new year.
> [FvL]To start the new year let me offer a little theorem:your point is the isogonal conjugate of the infinite point of the
> If A'B'C' is a circumcevian triangle [of point P], and A"B"C" are the
> reflections of
> A'B'C' through the sides of ABC, then the circles (ABC), (A"B"C),
> and (AB"C") are concurrent in one point.
direction which is perpendicular to HP.
notice that ABC and A"B"C" are perspective iff P lies on the Jerabek
hyperbola or at infinity.
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