10919Re: [EMHL] Feuerbach and pedal triangles
- Dec 1, 2004Dear Eric,
[ED]: I conjecture the following generalization:
>Let O be the circumcenter and I the incenterYour conjecture is correct. The locus of the perspector is the Jerabek
>The perpendiculars from each excenter to the line joining the
>Feuerbach point with the corresponding vertex of the pedal triangle
>of any point on OI are concurrent.
>The following questions intrigue me:
>==> what is the locus of the perspectors ?
hyperbola of the excentral triangle.
With reference to ABC, this has equation
bc(b-c)x^2 + ca(c-a)y^2 + ab(a-b)z^2 = 0.
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