Sorry, an error occurred while loading the content.

## Random Though about inductors

Expand Messages
• As I am sitting here rewinding a transformer for the 3rd time in two days (The first time I ran out of window area before I finished winding. The second time
Message 1 of 8 , Mar 19, 2013
• 0 Attachment
As I am sitting here rewinding a transformer for the 3rd time in two days (The first time I ran out of window area before I finished winding. The second time I nicked the insulation on the magnet wire and developed a short between the primary and secondary.), I began to contemplate magnetics in general and started to ponder something that I can't quite figure out yet. If you wind an inductor with stranded wire (or multiple parallel solid wires) why is it that you do not end up with N inductors in parallel, where N is the number of strands used to wind the part? E.g. Say I wind 10 turns on a core with an Al value of 100mH/1000T^2, I would expect to get an inductor of 10uH. Now say I needed to use 2 strands of #28AWG wire to carry the current load, why is it that I don't have two 10uH inductors in parallel or 5uH when it's all said and done? I'm sure it has something to do with the flux coupling in the core but right now I don't see it. Perhaps when my mind is not dulled by counting turns. Speaking of which was that #74 or #75?...Crap...1...2...3...

Shawn
• Shawn, ... solid wires)... Are you contemplating that these wire strands are insulated from each other? If so, consider this information in bi-filar winding of
Message 2 of 8 , Mar 20, 2013
• 0 Attachment
Shawn,

> ...If you wind an inductor with stranded wire (or multiple parallel
solid wires)...

Are you contemplating that these wire strands are insulated from each other?

If so, consider this information in bi-filar winding of coils:

http://en.wikipedia.org/wiki/Bifilar_winding

http://users.catchnet.com.au/~rjandusimports/balun_winding.html

Daniel
• Don t forget Litz wire coils, Daniel... Randy ... -- I am using the free version of SPAMfighter. SPAMfighter has removed 581 of my spam emails to date. Get the
Message 3 of 8 , Mar 20, 2013
• 0 Attachment
Don't forget Litz wire coils, Daniel...

Randy

On 3/20/2013 6:54 AM, D. Daniel McGlothin wrote:
>
> Shawn,
>
> > ...If you wind an inductor with stranded wire (or multiple parallel
> solid wires)...
>
> Are you contemplating that these wire strands are insulated from each
> other?
>
> If so, consider this information in bi-filar winding of coils:
>
> http://en.wikipedia.org/wiki/Bifilar_winding
>
> http://users.catchnet.com.au/~rjandusimports/balun_winding.html
> <http://users.catchnet.com.au/%7Erjandusimports/balun_winding.html>
>
> Daniel
>
>

--
I am using the free version of SPAMfighter.
SPAMfighter has removed 581 of my spam emails to date.
Get the free SPAMfighter here: http://www.spamfighter.com/len

Do you have a slow PC? Try a Free scan
http://www.spamfighter.com/SLOW-PCfighter?cid=sigen

[Non-text portions of this message have been removed]
• ... I shouldn t have. Bi-filar, multi-filar, litz--the keys are: how the strands are insulated from each other; the arrangement of the insulated strands with
Message 4 of 8 , Mar 20, 2013
• 0 Attachment
> Don't forget Litz wire coils...

I shouldn't have.

Bi-filar, multi-filar, litz--the keys are: how the strands are
insulated from each other; the arrangement of the insulated strands with
respect to each other; and how those strand's ends are connected (and
especially, to which end of what other strand each end of the strands
are connected).

The connections are just the beginning. From there, other
considerations and concerns start to become important (and maybe
influence the connection decisions). Should there be interest, I can
point to reference materials and I'm sure others here can elaborate at
length.

Daniel
• It has to do with turns on the same core. If a different core, then you would be parallelling inductors. Basic equation is L, Henrys = 0.4 * pi * N^2 * Ac *
Message 5 of 8 , Mar 20, 2013
• 0 Attachment
It has to do with turns on the same core. If a different core, then you
would be parallelling inductors. Basic equation is

L, Henrys = 0.4 * pi * N^2 * Ac * 10e-8 / lg

N = number of turns
Ac = core cross-section in cm^2
lg = gap length for cut cores and laminates, or equivalent for
powder cores

From the above equation, it is irrelevant as to how many parallel
windings. It is based on core geometry and turns. As for flux and
saturation, that is a different equation that is based on material and
current.

Derek Koonce
DDK Interactive Consulting Services

On 3/19/2013 10:08 PM, sstandfast wrote:
>
> As I am sitting here rewinding a transformer for the 3rd time in two
> days (The first time I ran out of window area before I finished
> winding. The second time I nicked the insulation on the magnet wire
> and developed a short between the primary and secondary.), I began to
> contemplate magnetics in general and started to ponder something that
> I can't quite figure out yet. If you wind an inductor with stranded
> wire (or multiple parallel solid wires) why is it that you do not end
> up with N inductors in parallel, where N is the number of strands used
> to wind the part? E.g. Say I wind 10 turns on a core with an Al value
> of 100mH/1000T^2, I would expect to get an inductor of 10uH. Now say I
> needed to use 2 strands of #28AWG wire to carry the current load, why
> is it that I don't have two 10uH inductors in parallel or 5uH when
> it's all said and done? I'm sure it has something to do with the flux
> coupling in the core but right now I don't see it. Perhaps when my
> mind is not dulled by counting turns. Speaking of which was that #74
> or #75?...Crap...1...2...3...
>
> Shawn
>
>

[Non-text portions of this message have been removed]
• Interesting question! The key insight is probably this: The strength of a magnetic field around a wire is proportional to the total current through the wire.
Message 6 of 8 , Mar 20, 2013
• 0 Attachment
Interesting question!

The key insight is probably this: The strength of a magnetic field around a
wire is proportional to the total current through the wire. It doesn't
matter whether the wire consists of a single strand (carrying, say 1A) or
multiple strands (each carrying 1/n A).

A changing magnetic field induces a "back EMF" in the wire which is
proportional to the rate of change and which exactly balances the applied
voltage across the wire and limits the rate at which the current rises in
the wire. The back EMF is per unit length of the wire (e.g. 1V per cm).
Thus, again it doesn't matter whether the wire consists of a single or
multiple strands.

[Non-text portions of this message have been removed]
• ... The flux linking a coil is proportional to N * I. Where N is the number of turns and I is the current. You will get the same flux if you use one winding
Message 7 of 8 , Mar 21, 2013
• 0 Attachment
On 3/20/2013 12:08 AM, sstandfast wrote:
>
> As I am sitting here rewinding a transformer for the 3rd time in two
> days (The first time I ran out of window area before I finished
> winding. The second time I nicked the insulation on the magnet wire
> and developed a short between the primary and secondary.), I began to
> contemplate magnetics in general and started to ponder something that
> I can't quite figure out yet. If you wind an inductor with stranded
> wire (or multiple parallel solid wires) why is it that you do not end
> up with N inductors in parallel, where N is the number of strands used
> to wind the part? E.g. Say I wind 10 turns on a core with an Al value
> of 100mH/1000T^2, I would expect to get an inductor of 10uH. Now say I
> needed to use 2 strands of #28AWG wire to carry the current load, why
> is it that I don't have two 10uH inductors in parallel or 5uH when
> it's all said and done? I'm sure it has something to do with the flux
> coupling in the core but right now I don't see it. Perhaps when my
> mind is not dulled by counting turns. Speaking of which was that #74
> or #75?...Crap...1...2...3...
>
> Shawn
>
> _

The flux linking a coil is proportional to N * I. Where N is the number
of turns and I is the current. You will get the same flux if you use
one winding with 100 turns and 1 amp as you will with 2 windings of 100
turns with !/2 amp in each winding.

The other Howard

[Non-text portions of this message have been removed]
• Right, that s what I get for trying to think after 10:00 pm. When you parallel the strands, they each divide the total current by N (assuming each strand has
Message 8 of 8 , Mar 21, 2013
• 0 Attachment
Right, that's what I get for trying to think after 10:00 pm. When you parallel the strands, they each divide the total current by N (assuming each strand has equal impedance) thus the total amp-turns on the core remains constant. (Provided you wrap each strand with the same number of turns.) Since the core geometry is constant then the effective cross-sectional area (Ae) remains constant. That means that the total flux (B dot Ae) is constant and is equal to the sum of the flux contributions of each strand. That means that the integral volt-seconds remains the same and that means the slope of the E*dt vs I curve is constant and thus the inductance is constant. To represent it mathematically:

H = Ns*Is/Le; where Ns = # turns per strand, Is = Current in an individual strand, and Le = effective magnetic path length

Assuming that we have X number of parallel strands of equal resistance wound on the core and the total inductor current (Itot) remains constant then:

Is = Itot / X

That means that the individual flux density of each strand is:

Bs = u*H = u*((Ns*Is)/Le) = u*((Ns*Itot)/(X*Le))

where u = u0*ur and u0 is the absolute permeability of free space and ur is the relative permeability of the core material.

Thus the total flux in the core is:

Phi = Sum(A Dot Bs(i), i = 1, i=X) which equals:

Phi = X*Ae*Bs

Using Faraday's law, the integral volt-seconds is equal to the number of turns times the total flux or:

V*dt = Ns*Phi

Substituting what we know into this equation:

V*dt = Ns*X*Ae*Bs = Ns*Ae*X*u*((Ns*Itot)/(X*Le))

Simplifying the above yields:

V*dt = u*Ae*Itot*Ns^2/Le

We also know that L equals the slope of the line of the V*dt vs I curve so dividing both sides by Itot gives:

V*dt/Itot = L = u*Ae*Ns^2/Le which is the standard formula for inductance. You can also see that this equation is independent of X thus proving that you can wind as many parallel turns on a core as you want but you will always get the same inductance value. Another interesting thing would be to try and figure out what happens when you wind an inductor with multiple strands and unequal numbers of turns between them. I would think that the transformer action that occurs would attempt to balance the current through the windings so that all had an equal number of Amp-Turns. I.E. the winding with the most turns would carry the least current and all the other windings would carry a proportionally larger current. I predict that the total inductance will be the same in that case too, just with unequal current sharing between the parallel windings. I won't go into a derivation of those equations but it would be a fun exercise.

Thanks to everyone who helped get the light bulb to turn on. Like I said, I shouldn't be thinking late at night because it makes me question the simplest of truths.

Shawn

--- In Electronics_101@yahoogroups.com, Jan Kok <jan.kok.5y@...> wrote:
>
> Interesting question!
>
> The key insight is probably this: The strength of a magnetic field around a
> wire is proportional to the total current through the wire. It doesn't
> matter whether the wire consists of a single strand (carrying, say 1A) or
> multiple strands (each carrying 1/n A).
>
> A changing magnetic field induces a "back EMF" in the wire which is
> proportional to the rate of change and which exactly balances the applied
> voltage across the wire and limits the rate at which the current rises in
> the wire. The back EMF is per unit length of the wire (e.g. 1V per cm).
> Thus, again it doesn't matter whether the wire consists of a single or
> multiple strands.
>
>
> [Non-text portions of this message have been removed]
>
Your message has been successfully submitted and would be delivered to recipients shortly.