--- In Distillers@yahoogroups.com
, "Mike Nixon" <mike@s...> wrote:
> Try working it with kJ/mol ... it's much easier!
> Latent heat of vaporization of water is 40.639 kJ.mol and of
> 39.33 kJ/mol, so they are both pretty well much the same for any
> take a mean of 40 kJ/mol.
> In volume, 1 mol of water is 18.016 ml, and ethanol is 58.24 ml,
so the same
> amount of heat is needed to vaporize either volume. Just take it
> and the answers drop out fairly painlessly.
> What .... you want ME to do it????? :-))
> All the best,
> Mike N
> (Waddya mean? The dog ate your homework!!!!!)
Many thanks, Teech! :-))
Hmmm...guess I'll have to brush up on my self-taught Chem.Eng.
Eh bien, I have many books & such. So much to do, so little time.
And right now it's WHISKY TIME! :-)