--- In

Distillers@yahoogroups.com, BOKAKOB <bokakob@y...> wrote:

> I would like to ask if someone could post a sequence of

measurements and calculation formulas for computing power in a

boiler placed on a burner.

The following is an example of how to calculate the theoretical boil

up time for 10 gallons of water. The example uses two internal

elements, simply insert your assumed burner W in place of the

elements:

*********************

10 gallons = 36,291 g

1 cal = 1.163 x ee-6 kilowatt hour

1 cal is needed to raise 1 g water 1 degree C.

Using 1500W and a 3800W element = 5,300 W or 5.3 kilowatts

Raise 36,291 g of wash from 21 degree C to 78 degree C

36,291 g x 57 degree C = 2,071,836 cal needed.

2,071,836 cal x 1.163xee-6 kilowatt hour / 1 cal = 2.409 kilowatt

hour

2.409 kilowatt hour / 5.3 kilowatt = .45 hour or 27 min.

************************************

This is strictly theory and it will take longer to reach boil temp

due to losses to environment, heating the boiler itself, etc.

It would be difficult to directly calculate the magnitude of your

burner because of the losses and no way of knowing the extent of

those losses.

You can however record the actual power and time it takes to reach

boil temp in your setup then back through the above calculations to

determine the amount of energy wasted to losses, ie. the energy to

heat a 15 gallon stainless keg should be the same each time.

After determining the energy losses plus the energy to heat the

water you should be able to determine the magnitude of the burner.

If I didn't explain this well just let me know, I was in a hurry.

Hope it helps.