pH calculation check
- Could some keen chemist please check my calculations ....
Citric acid : C6O7H8 Mw=192, Ka=7.4x10-4
Tartaric acid : C4O6H6 Mw=150, Ka=1x10-3
1g in 1L of water gives 0.005521 mol/L which results in a pH of 2.7 ?
or to get a pH of 4 .... need only 0.022 g/L (eg 0.44g in 20L)
1g in 1L of water gives 0.00667 mol/L which results in pH of 1.45 ?
or to get a pH of 4 .... need only 0.016 g/L (eg 0.33g in 20L)
or to put it into more conventional terms, the 3/4 teaspoon of supermarket
grade citric acid I've added to 20L wash has probably acidified it WAY past
a "yeast happy" pH of 4 and it probably needs a decent dose of bicarbonate
of soda to neutralise it ?
...which...at a Mw of 84 g/mol for bicarb, means I should add about 0.44 g
of bicarb for each 1g of citric acid ?
I knew that high-school chemistry would finally come in usefull (just a
week too late)