## SV: [Distillers] Re: Saving power

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• Let’s say that we have no reflux, then vapours travels through the column and nothing happens. If we have little reflux: In the still the reflux meets warmer
Message 1 of 9 , Jun 1, 2003

Let’s say that we have no reflux, then vapours travels through the column and nothing happens.

If we have little reflux:

In the still the reflux meets warmer vapour from the lower part of the column, this makes the reflux boil and is leaving a stronger alcohol content in the vapour that travels upwards and meets more reflux. But if we have little reflux, the alcohol content will decrease quickly in the reflux so the alcohol in the vapour won’t be much stronger.

If we have plenty of reflux, every theoretical bottom in the still will act close to a pot still since the percentage in the reflux wont decrease much.

But lowering the power will maybe increase the efficiency of the packing and that will give you more theoretical bottoms in the still that compensates for lower relux ratio. The question is how much better the packing performs. Still another reason to test different power input in a short still.

It’s actually not that tricky to calculate the approximate alcohol content on every bottom in the still, at least if the still have physical bottoms, but if we approximate a theoretical bottom with scrubbers to 10 cm then

Johan

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Skickat: den 1 juni 2003 19:47
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Ämne: Re: [Distillers] Re: Saving power

what happens if it is just ideal conditions and there is no need for reflux? if vapors travel up the column and achieve refinement without reflux, why is it impossible?

rodmacd2000 <rmacdoug@...> wrote:

... (snip) but to get a 95% pure output you must be run under a reasonably high
reflux ratio (typically 10:1) and therefore your actual product
output will be something like 70 ml/hour.

I can be wrong I must say
Cheers, Alex...

A

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