--- In

Distillers@yahoogroups.com, suitcase1499@a... wrote:

> OK Harry,

> You lost me there I'm a dumbass country boy with a

little

> education not a Masters Degree (LOL) I have no idea what that

means. and I do

> have a metal ring not fire brick just steel with air holes to

direct the heat, a

> friend made it for me to fit the bottom of the keg. But it still

helps heat

> the barn I have it in an enclosed stall of 8' x 12' with a lot of

air holes

> believe me. Bottom line is how can I increase output would two

columns do it or

> just need two stills.???? Thanks

>

> Oh yeah I do have that internal heat source for myself 86 proof

plain sugar

> head : )

>

> Suitcase.

Sorry about the maths equation. The reason I gave it is to explain

why a small increase in column diameter gives such a large change in

performance or output, which is the "bottom line answer" to your

question. YOU NEED A BIGGER DIAMETER COLUMN to achieve bigger

output. (not shouting, just emphasising) :-)

All is relative. To increase output, you need to put more vapor up

the column. This requires more applied heat. More heat requires an

increase in column capacity, otherwise the vapor speed will increase

also, and reduce your purity.

The math on column capacity is easy to follow if you remember back

to school when they taught about circles. There are formulae for

circumference, area, cylinder volume (that's what we want).

To explain: Pi is always 3.1416 (near enough). R is radius of

column (half the diameter). ^2 is the previous number (radius)

multiplied by itself. Ht is the height of the column.

So for your column (cylinder) it's:

Pi x R^2 x Ht

3.1416 x 0.75" x 0.75" x 26" which gives 46 cubic inches.

If you increase the column to 2", then:

3.1416 x 1.0" x 1.0" x 26" which gives 81 cubic inches, nearly

double the volume or capacity.

This will enable you to increase the heat input without increasing

the vapor speed. Then you'll get your increased product output and

no loss of quality. But remember, all is relative. If you increase

the heat, you need to remove that increased heat at the condenser,

IOW up the coolant flowrate to match.

Slainte!

regards Harry