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• Within the 2-inches you have to be careful, a 3Cv or 3Kn type base as mounted if on a steep hill (and not on a road) only has a 2-inch move, so corner to
Message 1 of 5 , Apr 1, 2009
Within the 2-inches you have to be careful, a 3Cv or 3Kn type base as mounted if on a steep hill (and not on a road) only has a 2-inch move, so corner to corner would only allow mounted on a 40x30 base to turn, 40x40 or larger would require just over 2-inches, so not possible.

Sorry if this adds any confusion.

David Constable

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• I m confused.? Isn t an inch 2.54 Cm, thus 2 inches would be well over 4cm depth of a base.? Maybe I m missing your point. David ... From: David Constable
Message 2 of 5 , Apr 1, 2009
I'm confused.? Isn't an inch 2.54 Cm, thus 2 inches would be well over 4cm depth of a base.? Maybe I'm missing your point.

David

-----Original Message-----
From: David Constable <djconst2003@...>
To: DBA@yahoogroups.com
Sent: Wed, 1 Apr 2009 8:47 am
Subject: [DBA] (unknown)

Within the 2-inches you have to be careful, a 3Cv or 3Kn type base as mounted if on a steep hill (and not on a road) only has a 2-inch move, so corner to corner would only allow mounted on a 40x30 base to turn, 40x40 or larger would require just over 2-inches, so not possible.
?
Sorry if this adds any confusion.
?
David Constable

[Non-text portions of this message have been removed]

[Non-text portions of this message have been removed]
• ... You measure the corner that moves the farthest. If a 40x30 element spins 180 degrees on its center, every corner moves (according to the Pythagorean
Message 3 of 5 , Apr 1, 2009
On Wed, 1 Apr 2009, DLeecrenshaw@... wrote:

> I'm confused.? Isn't an inch 2.54 Cm, thus 2 inches would be well over
> 4cm depth of a base.? Maybe I'm missing your point.

You measure the corner that moves the farthest. If a 40x30 element spins
180 degrees on its center, every corner moves (according to the
Pythagorean Theorem) 50mm. 200p = 50.8mm, so that uses up essentially
your whole move (given that the Cv/Kn is in BGo).

DK
• ... If I understand correctly, he s refering to turning 180 degrees, in which case each corner effectively moves the length of the base s diagonal. The
Message 4 of 5 , Apr 1, 2009
On Wed, Apr 1, 2009 at 3:55 PM, <DLeecrenshaw@...> wrote:
> I'm confused.? Isn't an inch 2.54 Cm, thus 2 inches would be well over 4cm depth of a base.? Maybe I'm missing your point.

If I understand correctly, he's refering to turning 180 degrees, in
which case each corner effectively moves the length of the base's
diagonal. The diagonal of a 40x30 mm base is just under 2" so 3Cv in
BGo can turn in place, but the diagonal of a 40x40 mm base is a bit
over 2" so a LCh in BGo cannot.

--
Andreas Johansson

Why can't you be a non-conformist just like everybody else?
• This is one of those bass ackward assumptions I never play.? A unit turning 180 degrees would not take units on the front left and move them diagonally so they
Message 5 of 5 , Apr 1, 2009
This is one of those bass ackward assumptions I never play.? A unit turning 180 degrees would not take units on the front left and move them diagonally so they would continue to be on the front left.? They'd just turn around.? Therefore I have always just measured along the side edge.? I know, I'm a rebel.

David

-----Original Message-----
From: Andreas Johansson <andreasj@...>
To: DBA@yahoogroups.com
Sent: Wed, 1 Apr 2009 9:06 am
Subject: Re: [DBA] (unknown)

On Wed, Apr 1, 2009 at 3:55 PM, <DLeecrenshaw@...> wrote:
> I'm confused.? Isn't an inch 2.54 Cm, thus 2 inches would be well over 4cm depth of a base.? Maybe I'm missing your point.

If I understand correctly, he's refering to turning 180 degrees, in
which case each corner effectively moves the length of the base's
diagonal. The diagonal of a 40x30 mm base is just under 2" so 3Cv in
BGo can turn in place, but the diagonal of a 40x40 mm base is a bit
over 2" so a LCh in BGo cannot.

--
Andreas Johansson

Why can't you be a non-conformist just like everybody else?

[Non-text portions of this message have been removed]
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