## we can increase eficiency of rotating shaft.

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• Swamishriji Dear Sir, The figure is in cross section. As shown in figure, There are two cases. In each case there are two pulleys of same diameter. Each
Message 1 of 10 , Feb 13, 2006
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Swamishriji
Dear Sir,

The figure is in cross section. As shown in figure, There are two cases. In each case there are two pulleys of same diameter. Each pulley is of exactly circular shape and diameter is 4000mm.
In first case 50 K.G weight is fixed with each pulley as shown in figure. The center of each pulley is fixed. Between these two pulleys there is a stationary plate. Plate will remain stationary, while rotating the pulleys because centers of pulleys are fixed. 100 K.G weight is put on this plate. The force of this weight is applied on these two pulleys in vertical downward direction. Now we try to rotate slowly first pulley in clockwise direction and second pulley in anti clockwise direction. Lubrication is provided between the contact surfaces of stationary plate and pulleys.
In second case two pulleys of same diameter. 50 K.G weight is also fixed with each pulley, but there is no stationary plate and 100 K.G weight. Now we try to rotate slowly first pulley in clockwise direction and second pulley in anti clockwise direction.
As free body diagram in first case we can rotate pulleys using less moment of force. We can lift mass using less energy.   File is attached with this mail. Please open is to see diagram.

1. In case 1) the moment necessary to rotate each pulley is

M=(-G/2+G1*cos(alpha))*R
where:
G is weight of plate (=100 kg)
G1 is given weight (=50 kg)
alpha is angle of rotation of each pulley
2. In case 2) weigt of plate G=0.
Yours Truly,
Jigar Patel
5, Chankyanagar soc,
Nr Nandanvan Soc,
Nr Highway,
Mehsana-384002,
Gujarat
India
Ph:+91-9342539996,+91-2762-254342

Send instant messages to your online friends http://uk.messenger.yahoo.com

• Hello Jigar , sorry I do not see any benefit or positiv momentum in the experiment you described. For me, the force to lift the 100kg weight for a given amount
Message 2 of 10 , Feb 14, 2006
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Hello Jigar ,

sorry I do not see any benefit or positiv momentum in the experiment
you described. For me, the force to lift the 100kg weight for a
given amount of height is always the same.

Hubert
--- In AMBIENTENERGY@yahoogroups.com, jigar patel
<jig_patel_1982@...> wrote:
>
> Swamishriji
Dear Sir,
>
> The figure is in cross section. As shown in
figure, There are two cases. In each case there are two pulleys of
same diameter. Each pulley is of exactly circular shape and diameter
is 4000mm.
> In first case 50 K.G weight is fixed with
each pulley as shown in figure. The center of each pulley is fixed.
Between these two pulleys there is a stationary plate. Plate will
remain stationary, while rotating the pulleys because centers of
pulleys are fixed. 100 K.G weight is put on this plate. The force of
this weight is applied on these two pulleys in vertical downward
direction. Now we try to rotate slowly first pulley in clockwise
direction and second pulley in anti clockwise direction. Lubrication
is provided between the contact surfaces of stationary plate and
pulleys.
> In second case two pulleys of same diameter. 50 K.G
weight is also fixed with each pulley, but there is no stationary
plate and 100 K.G weight. Now we try to rotate slowly first pulley
in clockwise direction and second pulley in anti clockwise
direction.
> As free body diagram in first case we can rotate
pulleys using less moment of force. We can lift mass using less
energy. File is attached with this mail. Please open is to see
diagram.
>
> 1. In case 1) the moment necessary to rotate each pulley is
>
> M=(-G/2+G1*cos(alpha))*R
> where:
> G is weight of plate (=100 kg)
> G1 is given weight (=50 kg)
> alpha is angle of rotation of each pulley
> R is radius of pulley
> 2. In case 2) weigt of plate G=0.
>
> Yours Truly,
> Jigar Patel
> 5, Chankyanagar soc,
> Nr Nandanvan Soc,
> Nr Highway,
> Mehsana-384002,
> Gujarat
> India
> Ph:+91-9342539996,+91-2762-254342
>
>
>
> Send instant messages to your online friends
http://uk.messenger.yahoo.com
>
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Message 3 of 10 , Feb 15, 2006
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Message 4 of 10 , Feb 15, 2006
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Message 5 of 10 , Feb 15, 2006
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Message 6 of 10 , Feb 15, 2006
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Message 7 of 10 , Feb 15, 2006
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Message 8 of 10 , Feb 16, 2006
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Message 9 of 10 , Feb 16, 2006
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Message 10 of 10 , Feb 16, 2006
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