Christian Brabandt wrote:
> Hi Marc!
> On Mo, 18 Feb 2013, Marc Weber wrote:
> > I don't think that additional threads are going to help
> > There is an issue, and we should find a way to fix (IMHO).
> > Let me summarize again - and tell me if you feel differently.
> > Test cases:
> >  echo len(matchstr("\n",'\zs[^\n]\ze'))
> >  echo len(matchstr("\n","\\zs[^\n]\\ze"))
> > I expect both do the same, the difference is that the second as chr(10) in [^],
> > while the first has \n (which should be translated to chr(10).
> > However I obsorve that  returns 0 as expected , but  does return
> > 1, thus it matches \n even though I told Vim that I do not want to match
> > it. People told me this was because '.' is equal to [^\n].
> > Current situation: at least to be fixed
> > 1:
> > No matter whether '.' should behave like [^\n]
> >  and  should behave the same, right?
> > 2:
> > This should be documented.
> > (Do you all at least agree these two statments?)
> Bram, here is a patch, making [^\n] not match NL within the text and
> that also documents, that '.' matches CR and LF within the text.
> This makes both  and  behave the same and seems to better match
> the users expectations.
This isn't right, there are no NL characters in the text. There are NUL
characters which are stored as NL characters. That's an implementation
detail, which sometimes becomes visible to the user.
It's good to explain this in the docs. I'm not sure we actually should
change the behavior, it might not really take away much confusion.
DENNIS: You can't expect to wield supreme executive power just 'cause some
watery tart threw a sword at you!
"Monty Python and the Holy Grail" PYTHON (MONTY) PICTURES LTD
/// Bram Moolenaar -- Bram@...
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