--- In firstname.lastname@example.org
> > Which had to be expected. I think in a million random cubes,
> > three should be expected to be solvable in 13 moves or less.
> > four you found with 13f, can you please find out their optimal
> > solution lengths?
> For 1 million cubes, the theoretical distribution for the *optimal*
> maneuvers should look like this:
> 12f: ~1
> 13f: ~12
> 14f: ~160
> 15f: ~2200
> 16f: ~29000
> 17f: ~260.000
> 18f: ~690.000
> 19f: ~30.000
> 20f: probably less than 1
Ah, yes, I must've made a computation mistake. I tried again and get
12 expected cubes for 13f as well now. I did it like this:
First I looked at the right column in this statistic:
Multiplied the last number twice more with 13 (roughly the branching
factor). Multiply with a million, divide by 4.3e19.
Yeah I know, probably there's a statistic somewhere out there about
the overall distribution, but I don't know where.