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• Dear All, Are there any primes of the form 10^(2^k)+1 known for k 1 ? Yours, Mike H... Michael Hartley : Michael.Hartley@sit.edu.my Head, Department of
Message 1 of 3 , Nov 2, 2001
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Dear All,

Are there any primes of the form 10^(2^k)+1 known for k>1 ?

Yours, Mike H...

Michael Hartley : Michael.Hartley@...
Sepang Institute of Technology
+---Q-u-o-t-a-b-l-e---Q-u-o-t-e----------------------------------
"Often, when I am reading a good book, I stop and thank my
teacher. That is, I used to, until she got an unlisted number."
--Anon
• On Sat, 3 Nov 2001 11:26:10 +0800, MICHAEL HARTLEY ... Yves page says none through k=20; note that k=21 is reserved to be tested under the alias
Message 1 of 3 , Nov 2, 2001
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On Sat, 3 Nov 2001 11:26:10 +0800, "MICHAEL HARTLEY"
<Michael.Hartley@...> wrote:

>
>Dear All,
>
>Are there any primes of the form 10^(2^k)+1 known for k>1 ?
>
>Yours, Mike H...

Yves' page says none through k=20; note that k=21 is reserved to be
tested under the alias (10^2)^(2^19)

(Unless Proth specifically avoids testing bases which are perfect
squares, which I behavior I didn't observe with Proth 6.7).

Nathan
• On Sat, 03 Nov 2001 06:25:13 +0100, Marcel Martin ... Sorry - that was a careless typo on my part. k=20 itself has already been tested twice
Message 1 of 3 , Nov 2, 2001
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On Sat, 03 Nov 2001 06:25:13 +0100, Marcel Martin <znz@...>
wrote:

>>Yves' page says none through k=20; note that k=21 is reserved to be
>>tested under the alias (10^2)^(2^19)
>
>(10^2)^(2^19) = 10^(2^20), not 10^(2^21)
>
>Marcel Martin

Sorry - that was a careless typo on my part. k=20 itself has already
been tested twice (once by myself, in fact, unless my math is again
off).

Nathan
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