... Yes. The decimal representation of terminating rationals are not unique. This has to be adjusted for when doing things like using Cantor s diagonalMessage 1 of 3 , Jan 15, 2009View Source
> Extrapolating from the above, would it be true for me to say:
> 0.999... = 9/9 = 9/10 + 9/100 + 9/1000 + ... = 1 If I am wrong, then what is the rational fractions of:
Yes. The decimal representation of "terminating" rationals are not unique. This has to be adjusted for when doing things like using Cantor's diagonal argument to prove the reals are not countable.
So indeed 1.99999999999... is an even prime.