Browse Groups

• For those not familiar with Wilson s Theory: P is a prime number if, and only if, (P-1)! + 1 is divisible by P. Now take the number 1, (1-1)! + 1 = 0! + 1 = 2.
Message 1 of 2 , Mar 1, 2005
View Source
For those not familiar with Wilson's Theory: P is a prime number if,
and only if, (P-1)! + 1 is divisible by P.

Now take the number 1, (1-1)! + 1 = 0! + 1 = 2.
2 is divisible by 1, so why isn't 1 prime?
• Here is the definition of Wilson s Theorem from the Prime Pages: http://www.utm.edu/research/primes/notes/proofs/Wilsons.html Wilson s Theorem. Let p be an
Message 2 of 2 , Mar 1, 2005
View Source
Here is the definition of Wilson's Theorem from the Prime Pages:
http://www.utm.edu/research/primes/notes/proofs/Wilsons.html

Wilson's Theorem.
Let p be an integer greater than one. p is prime if and only if (p-1)! = -1 (mod p).

You seem to have left out the first part.

-----Original Message-----
From: paxtontravis [mailto:paxtontravis@...]
Sent: Tuesday, March 01, 2005 11:06 AM
Subject: [PrimeNumbers] Wilson's Theory and the number 1

For those not familiar with Wilson's Theory: P is a prime number if,
and only if, (P-1)! + 1 is divisible by P.

Now take the number 1, (1-1)! + 1 = 0! + 1 = 2.
2 is divisible by 1, so why isn't 1 prime?

Unsubscribe by an email to: primenumbers-unsubscribe@yahoogroups.com
The Prime Pages : http://www.primepages.org/

Your message has been successfully submitted and would be delivered to recipients shortly.
• Changes have not been saved
Press OK to abandon changes or Cancel to continue editing
• Your browser is not supported
Kindly note that Groups does not support 7.0 or earlier versions of Internet Explorer. We recommend upgrading to the latest Internet Explorer, Google Chrome, or Firefox. If you are using IE 9 or later, make sure you turn off Compatibility View.