yahoo ID:matholympaid I m korea I d like to share math information with you</font> <font color= green > over there .....under..Message 1 of 4238 , Jun 14, 2001View Sourceyahoo ID:matholympaid<br>I'm korea<br>I'd like to
share math information with
you</font><br><br><br><font color="green"><br>over there .....under..
under<br>my hompage and my cafe....<br>but it's korea
...still some of them is English<br>for example visit
<a href=http://my.dreamwiz.com/jaehoo2/site.htm target=new>http://my.dreamwiz.com/jaehoo2/site.htm</a><br>(part of my home page)there is much
information.....</font><br><font color="brown" size=3><br>Finallfy,,,,I"d like
to know.....<br>about american(or other country)
cafe or club.....like Math Olympaid<br>For example .in
korea, there is <a href=http://cafe.daum.net target=new>http://cafe.daum.net</a><br>it's many kinds
.....health.education.,sciencs.interest<br>math.music....and so on...<br>If there is this kind of cafe or
club...or association<br>please let me know!!~~ bye
bye~<br><br></pink>my e mail is
jaehoo2@...<br><br><br><br><a href=http://my.dreamwiz.com/jaehoo2 target=new>http://my.dreamwiz.com/jaehoo2</a><br>������
����������<br><a href=http://my.netian.com/~math target=new>http://my.netian.com/~math</a><br>�������� ������
����������������<br><a href=http://cafe.daum.net/olympaid target=new>http://cafe.daum.net/olympaid</a><br>������������ ��������~
((c/2 + x)^2 + y^2)^(n/2) + ((c/2 - x)^2 + y^2)^(n/2) = c^n where c/2 = x = -c/2 x^2+y^2=r^2 y/r=sin(T) Parametric form x= (+or- (-c^2 * r^2Message 4238 of 4238 , May 1, 2011View Source((c/2 + x)^2 + y^2)^(n/2) + ((c/2 - x)^2 + y^2)^(n/2) = c^n where c/2 >= x >= -c/2
x= (+or- (-c^2 * r^2 *(sin^2(T)-1))^(1/2))/c
T=0 to 2*pi Radians (but T=0 to pi/2 is sufficient).
I had to wait this long for the solving software to catch up.
Show that for all n>2 and c=rational, and for all x xor y rational, then x and y are never rational.
Doing so will give a "simple" proof of Fermat's Last Theorem.
--- In email@example.com, jeshields_98 wrote:
> I've just joined this club, and I have theorem
> for<br>you. It's also been posted on Spherical Cow but here
> seemed more appropriate, so I'll just throw it out
> here.<br><br>Theorem:<br><br>[y^2 + (c/2 - x)^2]^(n/2) +<br>[y^2 + (c/2 +
> x)^2]^(n/2) + c^n<br><br>Proposition 1:<br><br>If c can be
> solved in terms of x,y,n, the result is the equation for
> the set of curves that applies to triangles of an
> n-dimensional Pythagorean Theorem. (including the
> circle)<br><br>Proposition 2:<br><br>If c,y are rational, y not equal to
> zero, then x is never rational.<br><br>I have no way of
> knowing if proposition 2 is correct, but I HAVE derived
> the theorem and proposition 1. I will post the link
> to this if you would like some time in the future.