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• ## Re: Is isolated system can be unlimited power source?

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• Jul 15, 2010
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--- In gravitationalpropulsionstevenson@yahoogroups.com, "abelov0927" <abelov0927@...> wrote:
>
> Let's imagine that. An isolated system has infinite line of billiard balls. Each previous
>
> ball transfer whole it's own linear momentum to the next ball through a collision action.
>
> However, this next ball takes a hit away from his center of mass.(i.e. each next ball
>
> conducts rotational and translational motion.) Base on law of momentum conservation the last
>
> ball must take same linear momentum as a first ball on this line. However all balls start
>
> rotating on this line. It means, an isolated system with infinite line of balls will grow
>
> own energy to infinite value. If transfer all rotational kinetic energy of these balls to
>
> heat then this isolated system is unlimited power source.
>
> This is nonsense. This should not be happen in reality.
> It means,the rotational and translational motion transfer has a different behavior than
>
> translational motion.
>
> This essay is describe this problem and confirm a new theory with an experiment.
>
> Alex
>
> --- In gravitationalpropulsionstevenson@yahoogroups.com, "abelov0927" <abelov0927@> wrote:
> >
> > George.
> > Thank you for your peer review.
> > However, I think this effect might be to little for this experiment. The
> > electric current resistance of this graphite core has a big value.
> >
> > I made some changes on my site and this may be better helps to
> > understand and experiment result. Feel free to comment this.
> >
> >
> > Thank you.
> >
> > Alex
> >
> > Newton's First Law: "An object in motion will stay in motion and an
> > object at rest will stay at rest unless acted upon by an external force"
> > or "A body persists in a state of uniform motion or of rest unless acted
> > upon by an external force."
> > <http://en.wikipedia.org/wiki/Newton%27s_laws_of_motion>
> >
> > To use Newton's laws need to simplify each body of experiment to single
> > point object. Then these equations should apply for modeling these
> > experiments. However, real body's are not single point objects.
> >
> > To use Newton's mechanic equations for one type of motion, single event
> > can not induce two different movements in a single object. One event can
> > trigger only one kind of movement in each object. To describe a few
> > motions into one single object base on first Newton's law require one
> > unique event for each motion. Because an object should stay in one
> > motion (First Newton's Law). Not in many motions.
> >
> > The Newton's mechanic has two types of motions. Rotation and Translation
> > motions. Each of these motions has it's own law of momentum
> > conservation.
> >
> > The first experiment conforms to this rule, as there is only one
> > translational movement that is induced. These cylinders have repulsive
> > action aligned from their center of mass and each cylinder of this
> > experiment congruent to single point object. All pieces of these
> > cylinders conducts identical uniform motion.
> >
> > In the second experiment, one of these cylinders have repulsive action
> > aligned away from his center mass. Each piece of this cylinder conducts
> > it's own cycloidal motion with own trajectory. To simplify this cylinder
> > to single point object require to split cycloidal motion to two motions.
> > Rotation and translation motions. In this case, following first Newton's
> > law repulsive event should split to two independent events. Base on
> > this event splitting, the initial force should split to two independent
> > forces. Sum of these forces should be equal to initial force. Equations
> > with these forces will cover rotation and translation motions for one
> > object.
> >
> > [\{ \vec F_n = \vec F_1+\vec F_2 \\ \vec F_1\times t_1=m\times \vec v
> > \\ \\ F_2 \times t_2 \times R = I \times \omega]
> >
> > Where: Fn -net force for one event F1,F2 - sub forces for each event
> > t1,t2 - sub forces action time m - mass of object R - radius I -
> > moment of inertia of object v - translation velocity of object w -
> > angular velocity of object.
> >
> > However, to keep situation where one cylinder exhibits translation and
> > rotational movements for one event. These two movements are thus
> > considered as new type of movements. These movements are hence
> > standalone natural phenomenon. So it follows, the movement should have
> > its momentum and follow its own conservation of momentum.
> > Assuming the movement has a linear and angular momentum, the total
> > momentum of rotation with translation movement is:
> > [P_f= \sum P_j +\frac{1}{R_u}[\sum L_k]]
> > Where, Pj - linear momentum Lk - angular momentum Ru - unit radius
> >
> > The law of conservation of momentum for the translation movement with
> > rotation is:
> >
> > [\sum P_j +\frac{1}{R_u}[\sum L_k] = Const]
> >
> >
> >
> > --- In gravitationalpropulsionstevenson@yahoogroups.com,
> > "cambridgephysics" <hubrotherfour@> wrote:
> > >
> > >
> > > Hi,
> > >
> > > I was considering the compressive nature of wood in conjunction
> > with
> > > the pencils' hexagonal shape. Each edge of the hexagonal shape would
> > > possibly impart additional "bump" motion. Also some consideration of
> > > graphite core of pencil might show electromechanical static behavior
> > > when in motion next to another like object. Also considered a glass
> > rod,
> > > but again static electricity might alter behavior. Steel rods could
> > > impart a magnetic effect as well. In no way have I reviewed all
> > possible
> > > conflicts using copper rods, they are after all able to transmit
> > > electricity. Just some thoughts really, not derailing the experiment,
> > > just thought some more expanded results would help bolster your theory
> > > under peer review.
> > >
> > > Cheers,
> > >
> > > George
> > >
> > >
> > > --- In gravitationalpropulsionstevenson@yahoogroups.com, Alex Belov
> > > abelov0927@ wrote:
> > >
> > > Hi.
> > >
> > > How it could be change result?
> > >
> > > Anyway.
> > > Base on law of momentum conservation P=cosnt and momentum equation
> > > P=mv, the translation velocity of objects with identical mass must
> > have
> > > identical value and opposite direction. This law of momentum
> > > conservation for objects which conduct translation motions only.
> > >
> > > However one of these objects conduct rotation and translation motion
> > > together. This is a standalone phenomenon.
> > > However classical with own law of momentum conservation. However, the
> > > modern classical mechanic has rotation and translation motions only.
> > > With their own law of momentum conservation.
> > >
> > > Main Idea of this experiment was show the rotation with translation
> > > motion as a standalone natural phenomenon with own law of momentum
> > > conservation. This motion should be included into classical mechanics
> > > book.
> > >
> > > Thank you
> > >
> > > Alex
> > >
> > >
> > >
> > >
> > > --- On Thu, 2/4/10, cambridgephysics hubrotherfour@ wrote:
> > >
> > > From: cambridgephysics hubrotherfour@
> > > Subject: Gravitational Propulsion, Re: Please take a look on my
> > theory
> > > To: gravitationalpropulsionstevenson@yahoogroups.com
> > > Date: Thursday, February 4, 2010, 9:37 PM
> > >
> > > Â
> > >
> > >
> > > Hi, Â Â I tried to respond earlier to this experiment but must
> > > have made an error in posting.
> > > My question has to do with the use of perhaps a round copper rod
> > > of a pencil in performing this experiment? This regards physical
> > > properties that may influence results.
> > > Â Have you any results using anything other than pencils?
> > > Thankyou,
> > > George
> > >
> > > --- In gravitationalpropul sionstevenson@ yahoogroups. com,
> > "abelov0927"
> > > abelov0927@ ..> wrote:
> > > Â Hi.
> > > Please take a look on my site.
> > > Â This site contains theory, simulation and real experiment.
> > > Â The real experiment proves this theory.
> > > Â However, to prove this theory this experiment should be repeated
> > > many times by other research groups.
> > > Â
> > > Please read it and feel free to comment it.
> > > Â
> > > Thank You.
> > >
> >
>

For sure an enclosed system will pick up momentum, but theres always that enigma to solve for every action theres an equal opposite re-action, if you finish from were you started both actions are in the same place.
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