24 [AEA] M Z D 1 2 3 4 4X3X2X1 = 24 Cheers, Nitin ________________________________ From: Ascent Education CAT, Classes, GroupsMessage 1 of 4 , Mar 11, 2011View Source24[AEA] M Z D1 2 3 44X3X2X1 = 24Cheers,Nitin
From: "Ascent Education CAT, Classes, Groups" <cat@...>
Sent: Friday, March 11, 2011 6:22 PM
Subject: [2IIM CAT Prep] CAT Prep Qn : Permutation of Letters
Here is a relatively easy question on rearranging letters of a word.
In how many rearrangements of the word AMAZED, is the letter ‘E’ positioned in between the 2 ‘A’s (Not necessarily flanked)?
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I think 120 is the answer..... Here is the explanation: See E can be positioned at 2nd, 3rd, 4th and 5th positions only. When at 2nd position: 1st positionMessage 2 of 4 , Mar 13, 2011View Source
I think 120 is the answer.....
Here is the explanation:
See E can be positioned at 2nd, 3rd, 4th and 5th positions only.
When at 2nd position: 1st position is occupied by A only. then no. of permutations: 1*1*4! = 24 ways
When at 3rd position: 1st & 2nd position are occupied by A and any one of D,M or Z which can be done in 3*2 i.e. 6 ways and last three positions can be done in 3! ways . then no. of permutations: 6*1*3! = 36 ways
When at 4th position: 3*3*2*1*2! = 36 ways
When at 5th position: 4!*1*1 = 24 ways
So total no. of arrangements = 24+36+36+24 = 120 ways
If you think this is incorrect or have any doubts, please reply to this.