Browse Groups

• ## Re: [2IIM CAT Prep] CAT Number Theory - Questions on Remainders

(4)
• NextPrevious
• 1. 7^45 = 7(7^44) = 7(2401)^11 = 7(01)^11 = 7(01) = 07. 2. 3^90 + 5^90 = 9^45 + 25^45 is always divisible by (9 + 25) = 34. So remainder is zero. 3. 4 values -
Message 1 of 4 , Nov 10, 2010
View Source
1. 7^45 = 7(7^44) = 7(2401)^11 = 7(01)^11 = 7(01) = 07.
2. 3^90 + 5^90 = 9^45 + 25^45 is always divisible by (9 + 25) = 34. So remainder is zero.
3. 4 values - 1, 5, 7, 11.

From: Rajesh Balasubramanian <rajesh@...>
To: ascent4cat@yahoogroups.com
Sent: Mon, November 8, 2010 10:57:25 PM
Subject: [2IIM CAT Prep] CAT Number Theory - Questions on Remainders

Hi all,

Here are a few more questions on Number Theory based on remainders. They have also been posted at ou blog - http://iimcat.blogspot.com/2010/11/questions-on-number-theory-remainder.html.

1. What are the last two digits of the number 7 45 ?

2. What is the remainder when we divide 390 + 590 by 34?

3. N2 leaves a remainder of 1 when divided by 24. What are the possible remainders we can get if we divide N by 12?

Cheers all,
Rajesh
99626 48484
New CAT2011 batches starting @ Chennai
Nov 13th @ Velachery, Nov 20th @ Mylapore

Your message has been successfully submitted and would be delivered to recipients shortly.
• Changes have not been saved
Press OK to abandon changes or Cancel to continue editing
• Your browser is not supported
Kindly note that Groups does not support 7.0 or earlier versions of Internet Explorer. We recommend upgrading to the latest Internet Explorer, Google Chrome, or Firefox. If you are using IE 9 or later, make sure you turn off Compatibility View.