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• Given 3^x=5^y=(75) ^z. then find xy/2x+y..? options-1. z2. z/23. 2z4. 1 solution:-  3^x=5^y=(75) ^z=k   x=log(k) / log 3   ; y=log(k) / log 5  ; z=log(k)
Message 1 of 5 , Mar 5, 2010
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 Given 3^x=5^y=(75) ^z.then find xy/2x+y..?options-1. z2. z/23. 2z4. 1solution:-  3^x=5^y=(75) ^z=k  x=log(k) / log 3   ; y=log(k) / log 5  ; z=log(k) / log75xy/2x+y = {log(k)/log3} {log(k)/log3}                  """""""""""""""""""""""""""""""""'                 2[log(k)/log3] + [log(k)/log5]log(k) is canceled from neu and den and take lcm and solve it  to=   log(k) / 2log5 + log3  = log(k)/log [(5^2)*3]= log(k)/log 75 = zanswer is 1. z

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• 3^x=5^y=75^z xy/(2x+y)? Answer of this Q as fallows log(3^x)=log(75^z) x=zlog75/log3 log(5^y)=log(75^z) y=zlog75/log5
Message 1 of 5 , Mar 7, 2010
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