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• hi mansi this is kuldeep here, here is the solution for ur problem: there are 2 stations 600 km apart. a train starts from first station A and moves towards B
Message 1 of 12 , Sep 29, 2005
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hi mansi this is kuldeep here,
here is the solution for ur problem:
there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?
sol:
train which starts from A towards B covered 50 kms in 2 hrs as it started 2 hr earlier then the other train.
so to meet both of these train ,these trains have to cover 550 kms with a speed of 60 kms/hr (25+35)
so time taken is 550/60 hr.
so in 550/60 hr train which started from B coveres (550*35)/60=320.833333 kms
so this train at this moment is 600 - 320.833333 = 279.16667 kms

Thanks & Regards,
KUldeep Kumar,
Project Engineer.
Wipro Technologies,
Bangalore.
Mobile: 09886632541
Extn.: 84261

From: ascent4cat@yahoogroups.com [mailto:ascent4cat@yahoogroups.com] On Behalf Of mansi suri
Sent: Wednesday, September 14, 2005 12:41 PM
To: ascent4cat@yahoogroups.com
Subject: Re: [ascent CAT] TDS

hi Ankur
this is mansi ihave a problem on speed time and distance so please help me.the ans i know but i am not getting the exact solution .
there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?
the ans for this is 279.166 km
hope to get the ans soon
Ankur Aggarwal <ankur.pegasus@...> wrote:

1)       2km in ¼ km course = 8 rounds race

middle of 6th round means 5 and a half round and since that round means an overlap. 4 ½ for the second party.

11km for a = 9 km for b

2 km for a = 18/11 km for b

difference = 4/11km

2)       250 A = 200 B

550A = 440 B

so he is short by 10 m

3)       let faster takes t minutes for one round.

So in each overtake, number of rounds by slower = 30 /( t+1)

Since faster has a lead of 1 round

30 / (t +1) = 30 /t + 1

obvious factors come to be 5,6 minutes to take a round

On 8/16/05, praveena_panic3 <praveena_panic3@...> wrote:
hey people
plz help me out with these probs.

1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps
B in the middle of his 6th round.By what dist will A win  at the
same rate of running?(ans 4/11 km)A & B ru
as per the explanation in my book when A runs 5&1/2 rounds B runs
only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz
explain the entire prob.

2.A & B start frm the same point to run in opp directions around  a
circular path 550 yards in length,A giving B a start of 100
yards.They pass each other when A has run 250 yards.who will come
first to the starting point & at what dist will they be apart?(ans -
A,10 yards)

3.Two runners run in the same direction along a circular track 2 km
long.the faster overtakes the slower on e every 30 min.find their
speeds if the faster one completes a round one min sooner than the
other.(ans 24 km/hr & 20km/hr)

plz plz plz explin in detail.
thanks folks.

http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/DxDolB/TM
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• Hi, In two hours the distance travelled by Train A would be 50 Kms. Remaining distance is 550. Suppose they meet at a point X after some time t . then
Message 1 of 12 , Sep 29, 2005
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Hi,

In two hours the distance travelled by Train A would be 50 Kms.
Remaining distance is 550.

Suppose they meet at a point 'X' after some time 't'.

then 25*t=X----1

35*t=550-X---2.

Solving 1 and 2 value of X = 229.166...

then the distance from A will be 229.166 + 50 = 279.166...

Method II:
In two hours the distance travelled by Train A would be 50 Kms.
Remaining distance is 550.

Relative speeds of the trains coming in opposite directions is V1+V2 = 25+35 = 60.
Time Taken to cross = 550/60= 55/6.

Distance from A = (55/6)*25+50 = 279.166....

Regards,
Rajasekhar.N

mansi suri <samisweetme@...> wrote:
hi Ankur
this is mansi ihave a problem on speed time and distance so please help me.the ans i know but i am not getting the exact solution .
there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?
the ans for this is 279.166 km
hope to get the ans soon
Ankur Aggarwal <ankur.pegasus@...> wrote:

1)       2km in ¼ km course = 8 rounds race

middle of 6th round means 5 and a half round and since that round means an overlap. 4 ½ for the second party.

11km for a = 9 km for b

2 km for a = 18/11 km for b

difference = 4/11km

2)       250 A = 200 B

550A = 440 B

so he is short by 10 m

3)       let faster takes t minutes for one round.

So in each overtake, number of rounds by slower = 30 /( t+1)

Since faster has a lead of 1 round

30 / (t +1) = 30 /t + 1

obvious factors come to be 5,6 minutes to take a round

On 8/16/05, praveena_panic3 <praveena_panic3@...> wrote:
hey people
plz help me out with these probs.

1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps
B in the middle of his 6th round.By what dist will A win  at the
same rate of running?(ans 4/11 km)A & B ru
as per the explanation in my book when A runs 5&1/2 rounds B runs
only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz
explain the entire prob.

2.A & B start frm the same point to run in opp directions around  a
circular path 550 yards in length,A giving B a start of 100
yards.They pass each other when A has run 250 yards.who will come
first to the starting point & at what dist will they be apart?(ans -
A,10 yards)

3.Two runners run in the same direction along a circular track 2 km
long.the faster overtakes the slower one every 30 min.find their
speeds if the faster one completes a round one min sooner than the
other.(ans 24 km/hr & 20km/hr)

plz plz plz explin in detail.
thanks folks.

http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/DxDolB/TM
--------------------------------------------------------------------~->

Ascent Education
An IIM Alumni Venture
Class for CAT, XAT, GRE, GMAT
http://www.ascenteducation.com

Archives of past CAT questions can be viewed at http://questions.ascenteducation.com

IIM CAT Preparation tips at
http://iimcat.blogspot.com

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• Hey Mansi, Here is the explaination for ur query on TDS:- In the 2 hours before train B leaves - train A already covers 50 kms - @25kmph. Now, when train B
Message 1 of 12 , Oct 2, 2005
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Hey Mansi,
Here is the explaination for ur query on TDS:-

In the 2 hours before train B leaves - train A already covers 50 kms - @25kmph.
Now, when train B leaves, the distance left to be covered amongst them is 550
kms. (600 - 50 ) Their relative speed for this time would be 25 + 35 =
60kmph . So now to cover 550 kms at that speed will take 9.16 hrs. Multiply
this with 25 kmph to get the distance travelled by train A - after train B
left station B. That will come out to be 229 kms. Add 50 kms (the initial
distance travelled by train A) to this and VOILA you have 279 kms. Hope you
understand..If not...do mail back and ask..

Akshay

Quoting mansi suri <samisweetme@...>:

> hi Ankur
> me.the ans i know but i am not getting the exact solution .
> there are 2 stations 600 km apart. a train starts from first station A and
> moves towards B at the rate of 25km\h. after 2 hours another train from
> station B at hte rate of 35km\h. how far from A will they cross each other?
> the ans for this is 279.166 km
> hope to get the ans soon
> Ankur Aggarwal <ankur.pegasus@...> wrote:
>
> 1) 2km in ¼ km course = 8 rounds race
>
> middle of 6th round means 5 and a half round and since that round means an
> overlap. 4 ½ for the second party.
>
> 11km for a = 9 km for b
>
> 2 km for a = 18/11 km for b
>
> difference = 4/11km
>
>
>
> 2) 250 A = 200 B
>
> 550A = 440 B
>
> so he is short by 10 m
>
>
>
> 3) let faster takes t minutes for one round.
>
> So in each overtake, number of rounds by slower = 30 /( t+1)
>
> Since faster has a lead of 1 round
>
> 30 / (t +1) = 30 /t + 1
>
> obvious factors come to be 5,6 minutes to take a round
>
>
> On 8/16/05, praveena_panic3 <praveena_panic3@...> wrote:hey people
> plz help me out with these probs.
>
> 1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps
> B in the middle of his 6th round.By what dist will A win at the
> same rate of running?(ans 4/11 km)A & B ru
> as per the explanation in my book when A runs 5&1/2 rounds B runs
> only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz
> explain the entire prob.
>
>
> 2.A & B start frm the same point to run in opp directions around a
> circular path 550 yards in length,A giving B a start of 100
> yards.They pass each other when A has run 250 yards.who will come
> first to the starting point & at what dist will they be apart?(ans -
> A,10 yards)
>
> 3.Two runners run in the same direction along a circular track 2 km
> long.the faster overtakes the slower one every 30 min.find their
> speeds if the faster one completes a round one min sooner than the
> other.(ans 24 km/hr & 20km/hr)
>
> plz plz plz explin in detail.
> thanks folks.
>
>
>
>
>
>
>
>
> Ascent Education
> An IIM Alumni Venture
> Class for CAT, XAT, GRE, GMAT
> http://www.ascenteducation.com
>
> Archives of past CAT questions can be viewed at
> http://questions.ascenteducation.com
>
> IIM CAT Preparation tips at
> http://iimcat.blogspot.com
>
>
>
>
>
>
>
>
>
>
> --
> "Life is a game; Either you win or you learn how to win"
>
> Ascent Education
> An IIM Alumni Venture
> Class for CAT, XAT, GRE, GMAT
> http://www.ascenteducation.com
>
> Archives of past CAT questions can be viewed at
> http://questions.ascenteducation.com
>
> IIM CAT Preparation tips at
> http://iimcat.blogspot.com
>
>
>
> ---------------------------------
>
>
> Visit your group "ascent4cat" on the web.
>
> To unsubscribe from this group, send an email to:
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• hi lemme get to the soltuion at the instant they meet A has travelled for t hrs say B then for t-2 hrs so use 25t+35(t-2)=600 solve for t you get 279.166 good
Message 1 of 12 , Oct 3, 2005
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hi lemme get to the soltuion
at the instant they meet A has travelled for t hrs say
B then for t-2 hrs so use

25t+35(t-2)=600
solve for t you get 279.166

good luck

mansi suri <samisweetme@...> wrote:
hi Ankur
this is mansi ihave a problem on speed time and distance so please help me.the ans i know but i am not getting the exact solution .
there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?
the ans for this is 279.166 km
hope to get the ans soon
Ankur Aggarwal <ankur.pegasus@...> wrote:

1)       2km in ¼ km course = 8 rounds race

middle of 6th round means 5 and a half round and since that round means an overlap. 4 ½ for the second party.

11km for a = 9 km for b

2 km for a = 18/11 km for b

difference = 4/11km

2)       250 A = 200 B

550A = 440 B

so he is short by 10 m

3)       let faster takes t minutes for one round.

So in each overtake, number of rounds by slower = 30 /( t+1)

Since faster has a lead of 1 round

30 / (t +1) = 30 /t + 1

obvious factors come to be 5,6 minutes to take a round

On 8/16/05, praveena_panic3 <praveena_panic3@...> wrote:
hey people
plz help me out with these probs.

1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps
B in the middle of his 6th round.By what dist will A win  at the
same rate of running?(ans 4/11 km)A & B ru
as per the explanation in my book when A runs 5&1/2 rounds B runs
only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz
explain the entire prob.

2.A & B start frm the same point to run in opp directions around  a
circular path 550 yards in length,A giving B a start of 100
yards.They pass each other when A has run 250 yards.who will come
first to the starting point & at what dist will they be apart?(ans -
A,10 yards)

3.Two runners run in the same direction along a circular track 2 km
long.the faster overtakes the slower one every 30 min.find their
speeds if the faster one completes a round one min sooner than the
other.(ans 24 km/hr & 20km/hr)

plz plz plz explin in detail.
thanks folks.

http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/DxDolB/TM
--------------------------------------------------------------------~->

Ascent Education
An IIM Alumni Venture
Class for CAT, XAT, GRE, GMAT
http://www.ascenteducation.com

Archives of past CAT questions can be viewed at http://questions.ascenteducation.com

IIM CAT Preparation tips at
http://iimcat.blogspot.com

<*> To visit your group on the web, go to:
http://groups.yahoo.com/group/ascent4cat/

<*> To unsubscribe from this group, send an email to:
ascent4cat-unsubscribe@yahoogroups.com

<*> Your use of Yahoo! Groups is subject to:
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Send instant messages to your online friends http://uk.messenger.yahoo.com

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•  sol for train que as for this for first two hour the first train move 50 km now remaining distance is 550. since both train r movin towards each other so
Message 1 of 12 , Oct 4, 2005
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sol for train que
as for this for first two hour the first train move 50 km now remaining distance is 550. since both train r movin towards each other so relative speed is 25+35=60km/h
so time to meet other is 550/60
and distance from st A = 50+(550/60)*25=279.166

On Wed, 14 Sep 2005 mansi suri wrote :

>hi Ankur
>  this is mansi ihave a problem on speed time and distance so please help me.the ans i know but i am not getting the exact solution .
>there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?
>the ans for this is 279.166 km
>hope to get the ans soon
>Ankur Aggarwal <ankur.pegasus@...> wrote:
>
>1)      2km in ¼ km course = 8 rounds race
>
>middle of 6th round means 5 and a half round and since that round means an overlap. 4 ½ for the second party.
>
>11km for a = 9 km for b
>
>2 km for a = 18/11 km for b
>
>difference = 4/11km
>
>
>
>2)      250 A = 200 B
>
>550A = 440 B
>
>so he is short by 10 m
>
>
>
>3)      let faster takes t minutes for one round.
>
>So in each overtake, number of rounds by slower = 30 /( t+1)
>
>Since faster has a lead of 1 round
>
>30 / (t +1) = 30 /t + 1
>
>obvious factors come to be 5,6 minutes to take a round
>
>
>On 8/16/05, praveena_panic3 <praveena_panic3@...> wrote:hey people
>plz help me out with these probs.
>
>1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps
>B in the middle of his 6th round.By what dist will A win  at the
>same rate of running?(ans 4/11 km)A & B ru
>as per the explanation in my book when A runs 5&1/2 rounds B runs
>only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz
>explain the entire prob.
>
>
>2.A & B start frm the same point to run in opp directions around  a
>circular path 550 yards in length,A giving B a start of 100
>yards.They pass each other when A has run 250 yards.who will come
>first to the starting point & at what dist will they be apart?(ans -
>A,10 yards)
>
>3.Two runners run in the same direction along a circular track 2 km
>long.the faster overtakes the slower one every 30 min.find their
>speeds if the faster one completes a round one min sooner than the
>other.(ans 24 km/hr & 20km/hr)
>
>plz plz plz explin in detail.
>thanks folks.
>
>
>
>
>
>
>
>
>Ascent Education
>An IIM Alumni Venture
>Class for CAT, XAT, GRE, GMAT
>http://www.ascenteducation.com
>
>Archives of past CAT questions can be viewed at http://questions.ascenteducation.com
>
>IIM CAT Preparation tips at
>http://iimcat.blogspot.com
>
>
>
>
>
>
>
>
>
>
>--
>"Life is a game; Either you win or you learn how to win"
>
>Ascent Education
>An IIM Alumni Venture
>Class for CAT, XAT, GRE, GMAT
>http://www.ascenteducation.com
>
>Archives of past CAT questions can be viewed at http://questions.ascenteducation.com
>
>IIM CAT Preparation tips at
>http://iimcat.blogspot.com
>
>
>
>---------------------------------
>
>
>    Visit your group "ascent4cat" on the web.
>
>    To unsubscribe from this group, send an email to:
>  ascent4cat-unsubscribe@yahoogroups.com
>
>
>
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>
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• hi ankur srry but i am not convinced with the approach you have taken to solve the race problem bcoz the place where you have written 11 km for A = 9 Km for B
Message 1 of 12 , Oct 6, 2005
View Source
hi ankur

srry but i am not convinced with the approach you have taken to solve the race problem bcoz the place where you have written

11 km for A = 9 Km for B

here it is rounds and not the distance either take 8 rounds instead of 2 km or go on with km that is 11 rounds=2.75 km and 9 rounds=2.25 kms

Hence the solution you have put up here for mansi is not correct I supppse .

For any problem in my explanation ,revert back to me.

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