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• hey groovy, that s the width of this pano - 192000 pixels :-) http://www.360cities.net/prague-18-gigapixels it seems that any larger gigapixels out there have
Message 1 of 8 , May 31, 2010
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hey groovy, that's the width of this pano - 192000 pixels :-)

http://www.360cities.net/prague-18-gigapixels

it seems that any larger gigapixels out there have been refocused to shoot each row (which i did not do, shooting this)

--- In PanoToolsNG@yahoogroups.com, "hd_de_2000" <der@...> wrote:
>
> While browsing some online gigapixel panoramas, I wondered what physical resolution limits exist based on fundamental optical laws. Combining diffraction limit & depth-of-field formulas yields a universal minimum hyperfocal distance h for photographing 360 degree panoramas:
>
> h = width^2 * 1.39 * 10^-8 m
>
> Some numbers: w=10000 pixel: h=1.39m
> w=192000 pixel: h=512m
>
> This limit is independent of lens and sensor, but may not be reached with some lens/sensor combinations.
>
> For close-up panoramas a similar formula for the minimum object distance a and a desired depth-of-field da may be derived:
>
> a/h = da/a (da << a)
>
> Example: if the desired depth of field is +/- 10%, then with the same numbers as above, the minimum object distance is 0.139m fo the 10000 pixel wide panorama, and 51.2m for the 192000 pixel wide panorama.
>
>
> Helmut Dersch
>
> PS
> The exact formula is
> h = width^2 * lambda/(4*pi^2).
> Probably someone has calculated that before, but I did find no reference.
>
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