... be ... I don't know god's algorithm , and i don't understand group theory , but in theory the limit could be 6-7 secondes if someone can find those 19-20...
Hello Ron, Could you tell a little bit more about your new approach? 1. How many moves in average for the first layer? 2. How many moves for the last corners?...
I think it takes usual computers longer then 15s to find an optimal path, so I don't see how the human brain could do it in 15s.... ... solved ... that...
no, its more of a thistlewaite approach. Its about 70-80 moves per solution without the use of any new algs. But once i start using more effiecint moves i...
Since Adrian is talking about an edge permutation, I'd suggest he would have to do this instead: r² U² r² (Uu)² r² u² LarsV ... two flipped edges on the...
... Algorithm] either, ... Just ask Him! Some gods are even smarter than computers, they can solve the cube in 5 moves, and with the feet. That's called...
Hi Guys, A lot of what has been discussed here in terms of getting faster has to do with looking ahead. But so far in contests people are given 15 seconds of...
It is an Idea, but is it practical? I do not have 5 speedcubes, most speedcubers have 2 some 3 speedcubes So I gues this can only be performed using normal...
I still have a few questions: First, what does all that do? Second, what's the difference between U and u? Also, what's a parity problem? Thanks! Adrian ... ...
When I first brought up the idea of limits in my cube log on my site, I was specifically talking about the Fridrich method with no other random memorized...
... These guys are very talented full time professionals. It takes them many years of full time work to learn all that. They don't just memorize moves, but...
"U(up)D(down)F(front)B(back)r(right)L(left)" <---- I think that r is supposed to be capitalized. "The asterisk for a counterclockwise twist" <---- I don't...
Hi all it's me...again If you are extremely devoted to cubing, it is possible to memorize that 1200 some algs for the LL. If each alg is 10-15 moves, and the...
Darn. Another problem. This time, I have an odd number of "edges" oriented incorrected at the last layer. Is there a good website which has all the algorithms...
Yes, I agree with the point Andy makes. Just wanted to clearify, defend, and add to these points, if it's ok.... I hope I'm not getting to annoying about these...
This would be "that other" alg that was posted when you first asked. I also posted Akimoto's version of it a while back that you can search for. Hemm...,...
I was teaching one of my friends how to solve the 4x4 last night, using the partitioned 3x3 method that we all know and love, detailed on Chris's site, i.e....
I found your reference of extended cross not being "pure fridrichs". While I don't know what your definition of pure is, I do assume EC to be just as pure as...
With the Zborowski-Bruchem method a 1-look last layer is possible...number of algs needed to learn, around 600 I think. 1. cross 2. 3 CE pairs 3. Last CE...
Like I just posted about 45 seconds ago..no need for 1200 algs for 1-look. saying zz method isn't correct, as no one is sure if Bruchem or Zoborowski came up ...
Sometimes I wish I was a super-computer...then I'd be faster than all of you....lol..:P -Richard ... __________________________________ Do you Yahoo!? The New...
I see what you're saying, and I think it's probably possible, but it seems like a lot more work to me to match up the corners like that than to just do it like...
My gut reaction is to say that it might not be as efficient but I say that only because I am ridiculously biased to the way I do it now, since I've done it...
Hi, ... There have been a few variants of Fridrich, like orienting the last layer edges while inserting the last F2L pair (was Dan Knights the first to do...
