Sorry Steve you did well as a start only (as John already did) but this is not the final answer ;) As I mentioned earlier, we can assume V1=0 (C is also...
Hello Kerim, This subject was beaten to death in the threads "Trick Question, Super Capacitor" and "Capacitors and Energy Loss" about one year ago. Readers...
You are right Howard and I remember this; but my question here is about a practical situation though assumed ideal to simplify the formula. I mean its answer,...
Hm. You are asking how much -additional- energy it takes to charge a capacitor from an initial voltage V1 to a higher voltage V2. So that should be equal to...
All you said is totally right, but it is not the final answer of my question. Okay... I think it is time to give another hint. First, let us re-write the...
... But how much energy is supplied by the power source to charge a capacitor from 0 to V1 volts? Hint it is not 1/2 x C x V1^2 The other Howard ... ...
I guess what Kerim is hinting at is that if you use a power supply with ZERO source impedance (an ideal voltage source) and set to V2 volts to charge the...
Ah -- "UK Stock". Additional US$20 freight charge. I guess I'll order a few from Newark and be happy. This equipment was designed in UK, so it's no surprise......
I will try again, assuming V1 = 0 as you said. You mentioned something about the ideal case, so I will assume the capacitor has no resistance or inductance....
In article <A3A08F23-3BE6-4DCB-9154-6E0B1CE82E19@...>, ... Ouch! wonder what shipping from the UK would really be? Let's see - weight 3.3g - couple in a...
Good work Jan... but the extra energy needed, you mentioned here, has also a formula (also in function of C, V1 and V2 only) and the power supply should...
Hi Ron, here is the hint again... The extra energy that the power supply should provide in the real world (I mean when R could be close to zero Ohm, but not...
Battery's are Us will custom make any battery pack you want. At least the stores in the Twin Citys will do this. ... From: Dave C <davec2468@...> To:...
Adding the additional specification, "How much energy we need, from a voltage supply, to charge a capacitor C from 0V to V2?" completely changes the question....
... fixed at V2 (the new voltage on C). Sorry. Ah ... but how much energy would have been necessary to adjust the knob to raise the supply voltage? ... I...
I am surprised how no one analyzed yet the simple circuit on LTspice for example and read the energies. The circuit is juat V, R and C. For instance, after...
... For the simple case when the capacitor's initial voltage is zero and charges up to a voltage V the energy supplied by a power supply is Energy = V x...
Yes, as you found out, in case V1=0 E (capasitor) = E (resistor) = 1/2 * C * V2^2 Now, you can repeat your previous steps for V1 not equal to 0 ;) Kerim...
... Okay... here is the answer in details: Vcc charges C via R Vc_ini = V1 Vc_max = Vcc = V2 E_v energy supplied by the voltage source E_c energy stored in C ...
I would like to interface some Positive TTL logic (0V to +5V) to an instrument that will only accept negative TTL logic (0V to -5V). Unfortunatly I can not...
Peter, Wow! It has been a long time since I worked with TTL logic and I never wrked ti hegative logic in the snce that there is negative power supply. I also...
As a follow on to Leon Robinson suggestion do a Google search for either "TTL to ECL Translators, "TTL to ECL Converters" or to TTL to "ECL Drivers" The other...
Thanks! I would have had no hope of deriving that, as I do not know calculus. Now... what if the major impedance in the circuit is an inductor? I'm having a...
Re-reading this, now I think you were in error by stating "negative TTL logic". I think you really did mean ECL. If the schematic you uploaded is the existing...
